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4x^2=-6.8x
We move all terms to the left:
4x^2-(-6.8x)=0
We get rid of parentheses
4x^2+6.8x=0
a = 4; b = 6.8; c = 0;
Δ = b2-4ac
Δ = 6.82-4·4·0
Δ = 46.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.8)-\sqrt{46.24}}{2*4}=\frac{-6.8-\sqrt{46.24}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.8)+\sqrt{46.24}}{2*4}=\frac{-6.8+\sqrt{46.24}}{8} $
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